[Naruto Sama]

Welcome To The Crisis Thread

Information:

This is a thread where the Tailedfox Community gathers in the hour of need. This could be anything, anything. You could be a person needing help with your homework, your teacher could be torturing you with a difficult maths problem which you dont understand at all, you ask for help in this topic and anyone can answer it for you. But it also could be simple stuff like ''how do I change my signature'' or ''where can I watch this anime''.

It's basically a thread for all your questions.

If this thread becomes popular by any chance, we will all learn new stuff which will help us through crisis times!

  Spoiler: People who contributed to this thread so far 

-Renzy
-Alpha522
-Temari 3.14159
-Milas
-Digital_Naruto
-Zim...
-Erosennin900
-Filip The Great
-Shino
-Naomi
-Kakashi Gaiden
-DarkShadowLurker

If you think you can help with anything at all, please do, even if its a little!

Make sure to Thank or Rep those people who help you, always nice ^.^

[Alpha_522]

lawl perfect xD Kinda struggling at this hw right now, I suck when it comes to story problem lawl

Problem 1
A commercial jet took off from city 1 for city 2, a distance of 2550 km, at a speed of 800 km/h. At the same time a private jet, traveling 900 km/h, left City 2 for City 1. How long after takeoff will the jet pass each other?

Problem 2
Wendy took a trip from Davenport to Omaha, a distance of 300 mi. She traveled part of the way by bus, which arrived at the train station just in time for Wendy to complete her journey by train. The bus averaged 40 mi/h and the train 60 mi/h. The entire trip took 5 and a half hour. How long did Wendy spend on the train?

Problem 3
Kiran drove from Tortula to Cactus, a distance of 250 mi. She increaseed her speed by 10 mi/h for 360-mi trip from cactus to Dry Junction. If the total trip took 11 hr, what was her speed from Tortula to Cactus?

Problem 4
A salesman drives from Ajax to Barrington, a distance of 120 mi, at a steady speed. He then increases his speed by 10 mi/h to drive the 150 mi from Barrington to Collins. If the second leg of his trip took 6 mins more time than the first leg, how fast was he driving between Ajax and Barrington

sidenote:
mi = miles

[Renzy]

2nd problem:

x+y=5.5
40x+60y=300

Solve the system... first problem... too much to type... the rest...too lazy to read..

[Alpha_522]

ight got prob 2 down lol. now the 3 of em T_T

thanks dude. much appreciated.

[Naruto Sama]

Problem 1
A commercial jet took off from city 1 for city 2, a distance of 2550 km, at a speed of 800 km/h. At the same time a private jet, traveling 900 km/h, left City 2 for City 1. How long after takeoff will the jet pass each other?

I'm also not the best with story problems in maths, but I can help a bit

speed = distance/time. this means time = distance/speed

now, lets say they pass each other at a distance x from city 1. so the 800km/h plane travels x km. that would mean the 900km/h plane traveled (2550 - x) km.

so, for the 800-plane, time = x/800

for the 900-plane, time = (2550 - x)/900

this is a pair of simultaneous equations with two unknowns. you can solve for time

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Problem 3
Kiran drove from Tortula to Cactus, a distance of 250 mi. She increaseed her speed by 10 mi/h for 360-mi trip from cactus to Dry Junction. If the total trip took 11 hr, what was her speed from Tortula to Cactus?

we will use speed = distance/time

let s be Kiran's average speed from Tortula to Cactus. and let t_1 be the time for the trip. so,

s = 250/t_1 ....................(1)

she increased her average speed by 10 to drive to Dry Junction, so her speed is (s + 10). and so,

s + 10 = 360/t_2 ..............(2)

you can solve those for t_1 and t_2. then set t_1 + t_2 = 11. then you can solve for s and find the required answer from that

[Naruto Sama]

Problem 4
A salesman drives from Ajax to Barrington, a distance of 120 mi, at a steady speed. He then increases his speed by 10 mi/h to drive the 150 mi from Barrington to Collins. If the second leg of his trip took 6 mins more time than the first leg, how fast was he driving between Ajax and Barrington

No surprise here, speed = distance/time is again our main formula.

there is a snag in this question though. note that the speed is given with hours as the unit of time, while the trip, they told you about time in minutes. we have to work in one kind of unit. lets change 6 minutes to hours. note that 6 mins = 0.1 hours.

now, let s be the speed he drove between Ajax and Barrington. then (s + 10) is the speed he drove from Barrington to Collins. let t be the time he took to drive from Ajax to Barrington. then (t + 0.1) is the time he took to drive from Barrington to Collins.

for the first trip then, s = 120/t .................(1)

for the second trip, (s + 10) = 150/(t + 0.1) .................(2)

again, simultaneous equations. you want to solve for s

[Alpha_522]

hmmm can you just post the equations like how renzy did. Then I can solve it from there

[Naruto Sama]

I dunno, thats how I would solve it...I aint an expert in story problems ^.^

[Renzy]

He gain you the equation for the 3rd problem

(250/x)+(360/x+10)=11

[Naruto Sama]

Originally Posted by Renzy

He gain you the equation for the 3rd problem

(250/x)+(360/x+10)=11

Exactly ^.^